3q^2-7q+4=0

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Solution for 3q^2-7q+4=0 equation:


Simplifying
3q2 + -7q + 4 = 0

Reorder the terms:
4 + -7q + 3q2 = 0

Solving
4 + -7q + 3q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(1 + -1q)(4 + -3q) = 0

Subproblem 1

Set the factor '(1 + -1q)' equal to zero and attempt to solve: Simplifying 1 + -1q = 0 Solving 1 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1q = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1q = 0 + -1 -1q = 0 + -1 Combine like terms: 0 + -1 = -1 -1q = -1 Divide each side by '-1'. q = 1 Simplifying q = 1

Subproblem 2

Set the factor '(4 + -3q)' equal to zero and attempt to solve: Simplifying 4 + -3q = 0 Solving 4 + -3q = 0 Move all terms containing q to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -3q = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -3q = 0 + -4 -3q = 0 + -4 Combine like terms: 0 + -4 = -4 -3q = -4 Divide each side by '-3'. q = 1.333333333 Simplifying q = 1.333333333

Solution

q = {1, 1.333333333}

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